π‘ Activity β Solutions
π‘ Activity β Solutions
πΉ Set A :
1οΈβ£ 6 Γ· 3 + 4 Γ 2
- 6 Γ· 3 = 2 β 4 Γ 2 = 8 β 2 + 8 = 10
2οΈβ£ 6 Γ 4 β 12 Γ· 3 β 8
- 6 Γ 4 = 24 β 12 Γ· 3 = 4 β 24 β 4 β 8 = 12
3οΈβ£ 4 Γ 4 β 3 Γ 3 β 16 Γ· 4
- 4 Γ 4 = 16 β 3 Γ 3 = 9 β 16 β 9 = 7 β 16 Γ· 4 = 4 β 7 β 4 = 3
4οΈβ£ 20 β (3 Γ 23 β 5)
- 3 Γ 23 = 69 β (69 β 5) = 64 β 20 β 64 = β44
5οΈβ£ (5 + 2)Β² β 9 Γ 3 + 2Β³
- (5 + 2)Β² = 7Β² = 49 β 9 Γ 3 = 27 β 2Β³ = 8 β 49 β 27 + 8 = 30
6οΈβ£ (7 β β9) Γ (42 β 3 + 1)
- β9 = 3 β (7 β 3) = 4 β (42 β 3 + 1) = 40 β 4 Γ 40 = 160
πΉ Set B :
1οΈβ£ 5 Γ (2Β² + 3) + (2Β³)Β²
- 2Β² = 4 β (4 + 3) = 7 β 5 Γ 7 = 35 β 2Β³ = 8 β 8Β² = 64 β 35 + 64 = 99
2οΈβ£ 6 Γ 2 + 5 Γ 1 + 4 Γ· 2 β 1
- 6 Γ 2 = 12 β 5 Γ 1 = 5 β 4 Γ· 2 = 2 β 12 + 5 + 2 β 1 = 18
3οΈβ£ 1 + (2 Γ (4 β 3 + 1) + 7) β 2
- (4 β 3 + 1) = 2 β 2 Γ 2 = 4 β 4 + 7 = 11 β 1 + 11 β 2 = 10
4οΈβ£ 10 + 6 Γ (3 β 2) Γ 8 Γ· 24 β 1
- (3 β 2) = 1 β 6 Γ 1 Γ 8 Γ· 24 = 48 Γ· 24 = 2 β 10 + 2 β 1 = 11
5οΈβ£ (20 β 18)Β³ Γ· 8 Γ 3 β 1
- (20 β 18) = 2 β 2Β³ = 8 β 8 Γ· 8 = 1 β 1 Γ 3 = 3 β 3 β 1 = 2
6οΈβ£ (2 + 1 β 3 + 1 + 4)Β² β 2 Γ 4
- (2 + 1 β 3 + 1 + 4) = 5 β 5Β² = 25 β 2 Γ 4 = 8 β 25 β 8 = 17
ο»Ώ
β Final answers (in order)
- Set A: 10, 12, 3, β44, 30, 160
- Set B: 99, 18, 10, 11, 2, 17
6 comments